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Calculate the activation energy Ea for N205 (g) —-> 2 N02 (g) + 1/2 02 (g). Given k (at 45.0 degrees celcius) = 5.79×10^-4 S-1 and k (at 60.0 degrees celcius)= 3.83 x 10^-3 S-1. (R=8.314J/K x mol)

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